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1
nuance9
How to check who user is?

  • 2004/9/8 14:02

  • nuance9

  • Just popping in

  • Posts: 19

  • Since: 2004/8/13


What would be the simplest way to access the UID of a logged in user? Is this variable already available in all XOOPS pages, or would I need to execute a new DB query?

I'm very new to Xoops, so I'm unsure of the guts of it's workings.

Thanks!
2
Dave_L
Re: How to check who user is?

  • 2004/9/8 14:38

  • Dave_L

  • XOOPS is my life!

  • Posts: 2277

  • Since: 2003/11/7


Example:

global $xoopsUser; // needed if within a function

$uid = is_object($xoopsUser) ? $xoopsUser->getVar('uid') : 0;

if ($uid > 0) {
   echo "User #$uid is logged in";
} else {
   echo "No one is logged in":
}
3
nuance9
Re: How to check who user is?

  • 2004/9/8 15:23

  • nuance9

  • Just popping in

  • Posts: 19

  • Since: 2004/8/13


Thanks.

I wanted xDirectory to only show the "modify" option if the listing submitter equals the current UID. With your help it is working now, thanks!

4
melmick
Re: How to check who user is?

  • 2004/10/22 10:55

  • melmick

  • Just popping in

  • Posts: 1

  • Since: 2004/10/22


nuance9,

How did you get this to work? This is exactly what we need xdirectory to do, re: only show the "modify" option if the listing submitter equals the current UID.

Thanks in advance for any help.

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