11
I am not sure what are you trying to achieve with it? What do you need it for? It seems like you're missing the $vidid variable. If you look at the function:
function xtubeShowVideo($vidid, $source, $screenshot, $picurl)
in singlevideo.php you're passing to it following values, incl. the $video_arr['vidid']:
$video['showvideo'] = xtubeShowVideo(
$video_arr['vidid'],
$video_arr['vidsource'],
$video_arr['screenshot'],
$video_arr['picurl']
);
and are receiving back the "$vidid" included:
'';
If you're using the same function, but the Video Code is missing in the return, then it seems like you didn't submit it to the function in the first place. So make sure that the value $video_arr['vidid'] is being submitted to the function correctly.