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i am using ajax to write the content for a block in xoops 2.3. However, I have no way to return back the content to the original block with its template file.
Is there any solution for returning the block content to the original template file instead of hard coding the html source in the ajax file? i.e. share the template file in ajax content for a block.
Structure:
blocks/test.php
blocks/test_ajax.php
template/test.html